What mole fraction of O2 is converted to O3 by the air purifier?

Question

It is claimed that one such system generates 4.00g O3 per hour from dry air passing through the purifier at a flow of 5.00 L/min. If one liter of indoor air contains .280g of O2.

 

The ozone reaction is:

3O2---->2O3

 

Answer 1

3O2---->2O3

0.280 g/L x 5.00 L/min = 1.4 g O2/min

1.4 g O2/min x 1 mole/32 g x 60 min/hr = 2.625 moles O2 /hr

2.625 moles O2 /hr x 2 moles O3/3 moles O2 = 1.75 moles O3 generated/hr

1.75 moles O3 x 48 g/mole = 84 g O3 generated

4.00g/84 g = 0.0476 fractional recovery = 0.0476 mole fraction of O2 converted