Calculate the volume of 0.15 M NaOH that would be necessary to neutralize 1.22x10^-3 moles of KHP

Question

How do I do this please help 

Answer 1

The reaction is:

KHC₈H₄O₄ + NaOH = NaKC₈H₄O₄ + H₂O

 

That makes the mole ratio of NaOH to KHP 1:1

 

That's convenient because that means that 1.22 x 10^-3 moles of KHP will be neutralized by 1.22 x 10^-3 moles of NaOH

 

Now how do you get 1.22 x 10^-3 moles of NaOH from 0.15M NaOH?

 

0.15M means 0.15 moles/liter

 

So if you want to get 1.22 x 10^-3 moles of NaOH out of a solution that is 0.15 moles per liter and you want to end up with volume (liters)... you can take the 1.22 x 10^-3 moles of NaOH and divide it by 0.15 moles/L and you would end up canceling the moles and you would get:

 

1.22 x 10^-3 moles/0.15 mol/L = 0.00813 L = 8.13 mL