Assuming that z = a+bi, we have l (a-2)+(b+1)i l = l (a-2)+(b-2)il
So, (a-2)2+(b+1)2 = (a-2)2+(b-2)2
b2+2b+1 = b2-4b+4
6b = 3 So, b = 1/2
Therefore, the set of all complex numbers satisfying the given equation is the set of all complex numbers with imaginary part 1/2.
Mark M.
tutor
For a complex number, a+bi, the real part is a and the imaginary part is b, the coefficient of i.
Mark M (Bayport, NY)
Report
03/01/17
Mark M.
03/01/17