If I had 15 mol Cl2 and 11 mol Fe which would be the limiting reactant in: 2Fe + 3Cl2 --> 2FeCl3

Question

 please help with chem homework please please please 

Answer 1

Hi,

use the mole ration from the reaction equation: 

- Fe:Cl_2:FeCl₃ = 2:3:2. This means that 2 moles of Fe reacts with 3 moles of Cl₂ to form 3 moles of FeCl₃. The ratio for this reaction does NOT change.

 

Next: 11 mol of Fe reacts with 3/2*11 = 16.5 moles of Cl₂. You only have 15 moles of Cl₂, so Cl₂ is the limiting agent.

15 moles of Cl₂ reacts with (2/3)*15= 10 moles of Fe. After the reaction 1 mole of Fe is leftover.

 

Good luck