Find the zeros of P(x) and its multiplicity

Question

the zeros of P(x)=x²+25 are

x1= ()+()i with negative imaginary part

its multiplicity is= 

 

x2= ()+()i with positive imaginary part 

its multiplicity is= 

Answer 1

P(x) = x^2 + 25

 

P(x) = x^2 - (5i)^2

 

P(x) = (x + 5i)(x - 5i)

 

x1= (0)+(-5)i with multiplicity 1

 

x2= (0)+(5)i with multiplicity 1