Andrew M. answered 02/20/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
distance = rate * time
If Pablo takes t hours to ride 15 miles
Then Jose takes (t+2) hours to ride 15 miles
Let Pablo's rate = P
Let Jose's rate = J
Pablo rides 5 times as fast as Jose so P = 5J
Pablo: d = rt
15 = 5J(t)
15 = 5J(t)
Jose: d = rt
15 = J(t+2)
5Jt = Jt + 2J
4Jt = 2J
4t = 2
t = 0.5 hours
Since 15 = 5J(t)
5J(0.5) = 15
2.5J = 15
J = 6
Jose rides at 6 mph
Pablo rides at 5J = 30 mph