
Parviz F. answered 03/01/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
a) Probability (Ace drawn from a full pack) = 4/52 = 1/13
b) Pr( drawing 4 out of rolling a die) = 1/6
c) C 2 4 ( 1/2) ^2 ( 1/2 ) ^2 =
4! / (2! * 2! ) (1/2) ^4 = 6/ 16 = 3 /8
There are 4 ^2 = 16 possible ways of outcome to be different combination of boys and girls.
{ bbbb, bbbg, bbgb, bbgg, bgbb, bgbg, gbbg , gbbb , bggg, gbbg ,gbgb, gbgg, ggbb,gggb,gggg}
You see that there are six cases marked italic are total number of cases that outcome appears as 2boys and 2 girls. the probability is 6/16 = 3/8 , exactly like flipping coin 4 times
possible cases where 2 heads and 2 tails appear.