Muhammad Hassaan S. answered 02/29/24
Experienced High School Teacher Specialized in Math
To count how many times the bit pattern "101001" can appear within an IP address, we need to determine how many possible positions this pattern can start from in the IP address.
An IPv4 address consists of 32 bits, divided into four octets, each containing 8 bits.
The pattern "101001" is 6 bits long, and an octet is 8 bits long. Therefore, we need to find out how many times we can fit a 6-bit pattern within an 8-bit octet.
Since we're sliding a 6-bit window over an 8-bit space, there are 3 starting positions within an octet where the pattern "101001" can fit.
So, within a single octet, the pattern "101001" can appear 3 times. Since an IP address has 4 octets, the total number of times the pattern "101001" can appear within an IP address is:
3×3×3×3=81
Therefore, the bit pattern "101001" can appear 81 times within an IPv4 address.
Muhammad Hassaan S.
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