3x+4y=7 (-3,2)

Question

Equations of the lines through the given point parallel to and perpendicular 

Answer 1

First, we need to put the given line in slope-intercept form.

 

4y = -3x + 7    ----->    y = (-3/4)x + (7/4)

 

 

Use the point-slope form to find the parallel and perpendicular lines.

 

y = mx - mx₁ + y₁

 

where:

m = slope

(x₁ , y₁) is the given point the line passes through

 

 

Parallel lines have the same slope.  Perpendicular lines have negative reciprocal slopes.

 

y = (-3/4)x - (-3/4)(-3) + 2   ---->  parallel line

 

Simplify this equation on your own.

 

 

y = (4/3)x - (4/3)(-3) + 2      ----->  perpendicular line

 

Simplify this equation on your own.