Tevin is 36 years old. Danielle is 26 years old. How many years ago was Tevin's age 2 times Danielle's age?

Question

i need to know the equation and answer to (A) Translate the given information into an equation using the variable x = how many years ago Tevin's age was 2 times Danielle's age. Your equation should contain 36, 26, and 2. Do not simplify your equation. (B) Tevin's age was 2 times Danielle's age years ago.

Answer 1

To translate, x years ago, Tevin was twice Danielle's age. To find both of their ages x years ago, we need to subtract x from their current ages. This gives us the following equation:

 

36 - x = 2(26 - x)

 

If you wish to determine how many years, then you simply solve this linear equation.

Answer 2

Hi Kim,

 

If x is how many years ago, then Tevin's age back then was 36 - x and so was Danielle's. We also know that Tevin's age was 2 times Danielle's. That gives us this equation:

 

(36 - x) = 2 * (26 - x)

 

Now we can solve for x:

 

36 - x = 52 - 2x

 

x = 16 years

 

We can check our answer. 16 years ago, Tevin was 20 and Danielle was 10. We can see that Tevin is exactly twice as old as Danielle, which confirms our answer.

 

Hope this helps!