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Question

An object has the mass of m=p+ 1÷ 3p+1 and a density p= P^2-1 Divided by 9p^2 +6p+1. Determine it's volume v, where p= m divided by v. State the restrictions on any variables

Answer 1

Density = mass/volume

Volume = mass/density

                 p+1

               -------

               3p+1

               --------------

Volume =   p^2-1

                --------

                9p^2+6p+1

 

Volume =  (p+1)(9p^2+6p+1)

               --------------------

                (3p+1)(p^2-1)

 

Volume = (p+1)(3p+1)^2

              -------------------

               (3p+1)(p+1)(p-1)

 

                    3p+1

Volume   =    -------

                     p-1

p-1≠0

p ≠ 1