in a party 100 people came & there were 100 burgers . 100 people were divided in three categories A,B &C. ,

Question

each person of type A ate 2 burgers,each person of type B ate 4 burgers,4-4 person of type C decide to share 1 burger. Calculate the no. Of person in each category.

Answer 1

I think the numbers are wrong. There aren't enough burgers.

The following is how you would solve a problem like this.

 

100 people came, so

 

A + B + C = 100.

 

C = 4 (4 people of type C decide to share 1 burger)

 

Combine the 2 equations to get:

 

A + B = 96.

 

A people ate 2 burgers, B people ate 4 burgers and the 4 C people ate 1 burger.

There were 100 burgers, so

 

2A + 4B + 1 = 100 or 2A + 4B = 99.

 

Now you have 2 equations and 2 unknowns.

 

 A  + B = 96

2A + 4B = 99.

 

Multiply the top equation by 2 and subtract the 2 equations:

 

   2A + 2B = 192

- (2A + 4B) = 99

           -2B = 93

 

Therefore, B = -46.5 and A = 143.5 (and C = 4).

 

Of course you can't have half a person or a negative number of people.

For a correctly defined problem of this sort, A, B, and C should be between 0 and 100.

 

I suggest that you check the numbers from the question and try to solve it again.