The perimeter of the rectangle is 276 yards. The length of the rectangle is 6 yards less than double the width. What are the dimensions of the rectangle?

Question

The perimeter of the rectangle is 276 yards. The length of the rectangle is 6 yards less than double the width. What are the dimensions of the rectangle?

Answer 1

If we let x = width, we can represent the length in terms of the width, using the clues from the problem.

 

"Six less than" implies subtraction and "double" implies multiplication, so the length is:

 

2x - 6

 

Now, we know that the perimeter P of a rectangle can be expressed as P = 2L + 2W, where L = length and W= width

 

So, we have 2(2x - 6) + 2x = 276

 

Can you now solve this for x?