Ram K. answered 01/09/17
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Let the forced be F. When it acts only on the mass m1, the acceleration is F/m1 = a
When it acts on the combined mass m1+m2, the acceleration is F/(m1+m2) = 1/3a.
Dividing the 2nd equation by the first, we have m1/(m1+m2) = 1/3, or m2/m1 = 2.