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## Comments

Ben,

Hmmm...I cannot picture how the poles are situated. This needs a picture or again....1000 words!

BruceSTo solve this problem you set up two equations. One for the x component of tension and one for the y component of tension.

T1*cos 30 - T2 cos 60 = 0; X equation

T1*sin 30 + T2 sin 60 = 32.8kg * 9.8 m/s^2 Y equation

If we multiply top equation by sin 60, bottom by cos 60 and subtract we get the following:

T1cos30sin60 + T1sin30cos 60 = 32.8*9.8*cos 60

0.75*T1 + .25T1 = 160.72n = T1

substitute this value of T1 into the first equationn

.86605 * T1 = 0.5 * T2

T2 = 278.38n

To solve this problem you set up two equations. One for the x component of tension and one for the y component of tension.

T1*cos 30 - T2 cos 60 = 0; X equation

T1*sin 30 + T2 sin 60 = 32.8kg * 9.8 m/s^2 Y equation

If we multiply top equation by sin 60, bottom by cos 60 and subtract we get the following:

T1cos30sin60 + T1sin30cos 60 = 32.8*9.8*cos 60

0.75*T1 + .25T1 = 160.72n = T1

substitute this value of T1 into the first equationn

.86605 * T1 = 0.5 * T2

T2 = 278.38n