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COIN WORD PROBLEM

A newspaper carrier has $4.10 in change. He has 4 more quarters than dimes but 3 times as many nickels as quarters. How many of each coin does he have.
He has this many Quarters=
He has this many Dimes=
He has this many nickels=

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Vivian L. | Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACHMicrosoft Word/Excel/Outlook, essay comp...
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Hi Renee;
total=$4.10
quantity of dimes=x
dimes=0.10x
quarters=0.25(x+4)=0.25x+1.00
nickles=0.05(3)(x+4)=0.15x+0.60
 
4.10=0.10x+0.25x+1.00+0.15x+0.60
Combine like terms...
4.10=0.50x+1.60
Let's subtract 1.60 from both sides...
4.10-1.60=0.50x+1.60-1.60
2.50=0.50x
Divide both sides by 0.50...
1.50/0.50=(0.50x)/0.50
5=x
 
quantity of dimes=5
quantity of quarters=9
quantity of nickles=27
 
Let's check our work...
4.10=[(0.10)(5)]+[(0.25)(9)]+[(0.05)(27)]
4.10=0.50+2.25+1.35
4.10=4.10
Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
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