Inactive Tutor answered 12/12/16
Tutor
New to Wyzant
Are you looking for the inverse function of
f(x) = (x-1)/(x+1)
Or just the inverse of (x-1)/(x+1)
The inverse of (x-1)/(x+1) is 1/[(x-1)/(x+1)] = (x+1)/(x-1)
Note: The inverse of x is 1/x
f(x) = (x-1)/(x+1)
Or just the inverse of (x-1)/(x+1)
The inverse of (x-1)/(x+1) is 1/[(x-1)/(x+1)] = (x+1)/(x-1)
Note: The inverse of x is 1/x
Popuri P.
12/12/16