Mark M. answered 12/12/16
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Retired Math prof with teaching and tutoring experience in trig.
Distance = (Rate)(Time)
Let x = speed of first plane
Distance traveled by first plane in 2 hours = 2x
Speed of second plane = x+100
Distance traveled by second plane in 1.5 hours = 1.5(x+100)
So, 2x + 1.5(x+100) = 3090
3.5x = 2940
x = 840 kph
The first plane flies at 840 kph, while the second plane travels 940 kph.