Andrew M. answered 12/12/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Distance = Rate*Time ... d=rt
Let b = boat speed in still water
Let c = current speed
rate downstream = boat speed plus current speed
rate upstream = boat speed minus current speed
downstream: 51 = 3(b+c)
upstream: 44 = 4(b-c)
We have two simultaneous equations to solve:
1. 3b+3c = 51
2. 4b-4c = 44
multiply equation 1 by 4 and equation 2 by 3 and add
to eliminate the variable c
1. 12b + 12c = 204
2. 12b - 12c = 132
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24b = 336
b = 336/24
b = 14 mph
Plug 14 in for b in either original equation and solve for c
3b+3c=51
3(14)+3c=51
42 + 3c = 51
3c = 9
c = 3 mph