The frequency of an electromagnetic wave varies inversely with the wavelength. If a wavelength of 200 meters has a frequency of 800 kilocycles per second.

Question

what frequency will be associated with a wavelength of 320 meters?

___ kilocycles per second will be associated with a wavelength of 320 meters.

Answer 1

f = k/λ

 

k = constant

 

800,000 Hz = k / (200 m) ⇒ k = 200*800,000 m/s = 160,000,000 m/s

 

For λ = 320 m,

 

f = k/λ = (160,000,000 / 320) Hz = 500,000 Hz