Tim C. answered 12/04/16
Tutor
5.0
(305)
Experienced, Effective Specialist in Praxis Math (5733 / 5003 / 5903)
Let x be the number of dimes
Since there are 85 total coins, the total number of quarters MUST be 85 - x
The total value of all the dimes is .10 multiplied by x = .10x.
The total value of all the quarters is .25 multiplied by 85 - x = .25(85 - x) <--- Must have parentheses!
The total value of all the coins is .10x + .25(85 - x)
Set this total value equal to the total value given and solve for x
.10x + .25(85 - x) = 16.75
.10x + .25(85 - x) = 16.75 .10x + 21.25 - .25x = 16.75 -.15x + 21.25 = 16.75 -.15x = -4.5 x = 30 Therefore there are 30 dimes and 55 quarters.

Tim C.
tutor
.10x + .25(85 - x) = 16.75
.10x + 21.25 - .25x = 16.75
-.15x + 21.25 = 16.75
-.15x = -4.5
x = 30
.10x + 21.25 - .25x = 16.75
-.15x + 21.25 = 16.75
-.15x = -4.5
x = 30
Can you determine the amount of dimes and quarters from this?
Report
12/04/16
Bailee J.
12/04/16