Zachary D. answered 12/07/16
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First, start with the balanced equation.
This is a combustion reaction
2C8H18 + 25O2 --> 16CO2 + 18H2O
Molar mass of octane = 114.23 g/mol
Molar mass of O2 = 32.00 g/mol
Convert grams to moles then multiply by the molar ratio
8.17g C8H18 x (1 mol C8H18/114.23 g) x (25 mol O2 / 2 mol C8H18) x (32.00 g O2/1 mol O2) = 28.61 g O2