2y2-3=-5y the 2y is squared

Question

2y2 is squared-3=-5y  I know the answer is  1/2, -3    But can you help me to know how to write it out. I am missing something. Thank you

Answer 1

Hi Roseland,

 

2y²-3=-5y

2y²+5y-3=0

2y²+6y-y-3=0

2y(y+3)-1(y+3)=0

(2y-1)(y+3)=0

 

2y-1=0  or  y+3=0

y=1/2 or y=-3

Answer 2

Hi Roseland;

I believe this is NOT...

(2y)²-3=-5y

I believe this is...

2y²-3=-5y

Let's add 5y to both sides...

2y²+5y-3=-5y+5y

2y²+5y-3=0

For the FOIL...

FIRST must be (2y)(y)=2y²

OUTER and INNER must add-up to 5y

LAST must be (3)(1) or (1)(3) and one number must be negative to render the product of -3.

(2y-1)(y+3)=0

Let's FOIL...

FIRST...(2y)(y)=2y²

OUTER...(2y)(3)=6y

INNER...(-1)(y)=-1y=-y

LAST...(-1)(3)=-3

2y²+6y-y-3=0

2y²+5y-3=0

(2y-1)(y+3)=0

Either or both parenthetical equations must equal zero...

2y-1=0

2y=1

y=1/2

y+3=0

y=-3

Answer 3

Rewrite as 2y² +5y-3 = 0

 

a=2  b=5  c =-3

 

-5± √5² - 4(2)(-3) / 2(2)

 

-5±√25+24 / 4

 

-5±7     (-5+7)/4 =2/4(which is 1/2)    (-5-7)/4 = -3

  4