
Gene G. answered 11/23/16
Tutor
5.0
(257)
You can do it! I'll show you how.
You can use AC factoring when the first coefficient is not = 1.
It's similar to simple factoring, but with a little more work in the middle.
ax2 + bx + c
Find two factors of the ac product that add up to b.
15x2 + 26x + 7
ac = (15)(7) = 105
Find the factors of 105. Some may repeat. 24 would factor into (2)(2)(2)(3).
3 |_105
5 |__35
7 |___7
1
You need to use all of the factors exactly once. Try splitting them into two groups until you find the right combination.
f1 = (3)(5) = 15
f2 = (7)(1) = 7
f1 + f2 = 22 Too small.
f1 = (3)(7) = 21
f1 = (5)(1) = 5
f1 + f2 = 26 That's it.
f1 = (5)(1) = 5
f1 + f2 = 26 That's it.
21 and 5 are the factors we need.
Split the middle term (26x) into 21x + 5x. (5x + 21x would work just as well!)
15x2 + 21x + 5x + 7
Group the terms and simplify the groups.
(15x2 + 21x) + (5x + 7)
3x(5x + 7) +1(5x + 7)
Factor out the (5x + 7)
(5x + 7)(3x+1)
Done