Craig, we first multiply a x c, or 15 x 7 = 105.
Now, we need two factors of 105 that add up to b, or 26.
5 and 21 work. 5x + 21x = 26x.
15x2 + 5x + 21x + 7
What do the first two terms have in common? 5x. 15x2 + 5x = 5x(3x + 1).
What about the second two? 7, right? 7(3x + 1).
Now we have 5x(3x + 1) + 7(3x + 1). Since the parentheses are both the same, what's in front goes into their own set.
(5x + 7)(3x + 1)
Hope this helps!