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Music (help please!!)

 Musical tones.  The note middle C on a piano is tuned so that the string vibrates at 262 cycles per second or 262 HZ (Hertz). The C note one octave higher is tuned to 524 HZ. The tuning for the 11 notes in between using the method called equal temperament is determined by the sequence an=262*2n/12. Find the tuning for the 11 notes in between. Round to the nearest Hz. Show and explain your work. 
 
PLEASE WALK ME THRU SOLVING THIS ENTIRE PROBLEM. 
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1 Answer

arepresents middle C
a2 represents c#
a2 = 262(2)2/12
a2 ≈ 262(2)0.1666.
a2 ≈ 262(1.1224)
a2 ≈ 294.07
 
Follow this pattern for the remaining 10 pitches.
 
This is generally done by mechanical means.

Comments

a3 = 262(2)3/12
a4 = 262(2)4/12
a5 = 262(2)5/12
See the pattlern?