g(x) = x3 + ax2 + 3x +6. Given g(-1) =2, find the remainder when g(x) is divided by (3x -2).

Question

x cube and ax square plss solve it i have to find the remainder it is a remainder theorem problem...

Answer 1

 The correct answer is 224/27. It is done 2 problems before.

 

  above : You have X^2/3 * ( -2) = - 2/3 X^2 , You have it - 4 X^2/3.

Answer 2

First, figure out a, the coefficient of x2, using the g(-1) = 2

-1+a-3+6 =2

2+a=2

a=0

 

 

        x²/3+2x/9+31/27

        ______________________________________________________

3x-2 |x³+0*x²+3x+6

         x³-2x²/3

         =======

             2x²/3+3x

             2x²/3-4x/9

            =========

                        31x/9+6

                        31x/9-62/27

                        =========

                                  224/27 = 8 and 8/27

 

Hope I did not make a mistake, given difficult interface for input.