Heather H. answered 11/14/16
Tutor
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Chemist with 2+ years of tutoring experience
Hi Deliesha!
*How many moles of methane in the tank?
So we know that at STP 22.4 L=1 mol of gas. The problem states that you have 1.00x10^5 L of gas so we can set up this problem:
1.00x10^5 L * 1 mol/ 22.4 L = 4.46 x 10^3 mol of gas
*How many grams of methane is this?
We can find that the molecular mass of methane (CH4) is 12.01*1+1.008*4=16.04 g/mol
4.46x10^3 mol * 16.04 g/mol = 7.16x10^4 g methane
*How many grams of CO2 in the same tank?
We go back to the first piece of information: 1.00x10^5 L of gas in the tank and solve the problem exactly the same way as we did for methane:
molecular mass of CO2= 12.01*1+16.00*2=44.01 g/mol
1.00x10^5 L * 1mol/ 22.4 L * 44.01g/mol= 1.96x10^5 g methane
I hope this helps! Feel free to let me know if you have further questions!