
Arturo O. answered 10/20/16
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They meet when they are both the same distance from Santa Monica.
v1 = speed of train 1 = 75 kph
v2 = speed of train 2 = 125 kph
Let t = travel time in hours of train 1
Then t - 2 = travel time in hours of train 2 (train 2 left 2 hours after train 1)
The travel distances must be the same:
d = v1t
d = v2(t - 2)
Then
v1t = v2(t - 2)
Plug in the speeds and solve for t:
75t = 125(t - 2)
(125 -75)t = 250
t = 250/50 hrs = 5 hrs
v1t = v2(t - 2)
Plug in the speeds and solve for t:
75t = 125(t - 2)
(125 -75)t = 250
t = 250/50 hrs = 5 hrs
They meet at distance
d = v1t = 75*5 km = 375 km
You get same result if you use
d = v2(t - 2) = 125*(5 - 2) km = 375 km