the length of a rectangle is 7 more than twice the width. If the perimeter is 50 units, what are the dimensions of the rectangle?

Question

the length of a rectangle is 7 more than twice the width. If the perimeter is 50 units, what are the dimensions of the rectangle?

Answer 1

L = 2W + 7

 

P = 2(L + W) = 50

 

⇒

 

2[(2W + 7) + W] = 50

 

4W + 14 + 2W = 50

 

6W = 36

 

W = 6

 

L = 2*6 + 7 = 19

 

Width = 6 units, Length = 19 units

Answer 2

L = 19, W = 6