How many second had Anne been walking at the point when the two girls had walked he exact same distance?

Question

Anne and Mary went for a walk. Anne started walking 1 minute earlier than Mary did. Anne walks at a speed of 6 feet per second. Mary walks at a speed of 8 feet per second. How many second had Anne been walking at the point when the two girls had walked he exact same distance?

Answer 1

We know that distance = rate x time

 

We know Anne walks at a rate of 6 ft/s and Mary walks at a rate of 8 ft/s

 

1 min = 60 sec, and Anne started walking 60 sec prior to Mary

 

If the amount of time Mary walked is x, then the amount of time that Anne walked is (x + 60)

 

Since we want to know when the two girls walked the same distance, we can form the following equation using the formula for distance

 

8x = 6(x + 60)

 

8x = 6x + 360

 

2x = 360

 

x = 180

 

So Mary walked for 180 sec and Anne walked for x + 60 = 180 + 60 = 240 sec