
Marco P. answered 02/06/14
Tutor
New to Wyzant
Organic Chemistry Tutor
In the reaction of A -> B then the question as you phrased it is accurate. But lets say we are talking about the formation of a diatomic molecule such 2O -> O2 then suddenly you must rephrase your question. Now the rate of product formation (O2) is half of the rate of reactant "disappearance" as you phrased it (I would go with reactant consumption rate). You could equally say that atomic oxygen (O) is being consumed at twice the rate that molecular oxygen (O2). The exact relation will be relative to coefficients of the balanced equations, meaning if three things mix to make something, it will be three times and not twice the reaction rate, etc.
In Chemistry, the rate of a reaction is written in the standard rate equation
A + B -> C
r = k[A]x[B]y
the top equation is just the reaction, says A and B make product C
the bottom equation is a differential equation that related the concentration of A and B. k is the reaction constant, a reaction-specific constant, and x and y are experimentally derived exponents that are often mistakenly replaced by the coefficient (which leads to an incorrect solution to the equation and wrong reaction rate).