This involves the formula: distance = rate x time
let plane 1 travel a distance of x miles
plane 2 travels a distance of (1100 - x) miles
the rate of plane 1 is y
the rate of plane 2 is (y + 200)
Of course, the time is 2 hours based on the info given in the problem
x = y(2) = 2y
(1100 - x) = (y + 200)(2)
1100 - x = 2y + 400
1100 - 2y = 2y + 400 (using substitution of x = 2y)
1100 = 4y + 400
700 = 4y
175 = y
Plane 1 travels at a rate of 175 mi/hr and
Plane 2 travels at a rate of y + 200 = 175 + 200 = 375 mi/hr