Alejandro L. answered • 10/03/16

Chemistry tutor (all areas) + Intro Astronomy

You first need to determine Henry's constant (Kh) at this temperature:

Kh = P(CO2)/[CO2(aq)]

where P(CO2) is the partial pressure of CO2 and [CO2(aq)] is the concentration of CO2 in solution. Thus,

Kh = (3.6 atm)/[(24.8 mL CO2)/(1000 mL H2O)] = 145.2 atm*mL H2O/mL CO2

Now use the new pressure and the calculated Henry's constant at 273K to solve for the concentration of CO2:

[CO2(aq)] = P(CO2)/Kh = (3.95x10-4 atm)/(145.2 atm*mL H2O/mL CO2) = 2.72x10-6 mL CO2/mL H2O

At this point you can probably assume that the volume of H2O won't change much after gas dissolution and looking up the density of CO2 at 273K (1.964 g/L) we can determine the molarity of CO2 in solution:

M = (2.72x10-6 mL CO2/mL H2O) x [(1.964 g CO2)/(1000 mL CO2)] x [(1 mole CO2)/(44.01 g CO2)] x [(1000 mL H2O)/(1 L H2O)] = 1.21x10^-7 M or 0.121 uM.