Nasr B. answered 09/30/16
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To answer this question you need to write a balanced chemical reaction:
2 H2(g) + O2(g) → 2 H2O(l)
We can calculate the mass of O2 needed to form 24.6 g H2O based on the stoichiometry of the reaction:
24.6 g H2O x (1 mol H2O/18 g H2O) x (1 mol O2/2 mol H2O) x (32.00 g O2 /1 mol O2) = 21.87 g O2
You can also verify that H2 is in excess in the reaction based on the stoichiometry of the reaction:
24.6 g H2O x (1 mol H2O/18 g H2O) x (2 mol H2/2 mol H2O) x (2.016 g H2 /1 mol H2) = 2.76 g H2
The mass of H2 needed is less than the real mass added at the beginning (2.9 g). This confirms that H2 is in excess.