
Steve S. answered 01/20/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
a.1.)
10^5 = p (1.08)^10 + p (1.08)^9 + ... + p (1.08)^2 + p (1.08)
10^5 / 1.08 = p (1.08)^9 + p (1.08)^8 + ... + p (1.08) + p
10^5 - 10^5 / 1.08 = p (1.08)^10 - p = p ( (1.08)^10 - 1 )
p = ( 10^5 - 10^5 / 1.08 ) / ( (1.08)^10 - 1 )
p = 10^5 ( 1 - 1 / 1.08 ) / ( (1.08)^10 - 1 )
p = 10^5 ( 0.08 / 1.08 ) / ( (1.08)^10 - 1 )
p ≈ $6,391.62
b.1.)
p = 10^5 ( 0.05 / 1.05 ) / ( (1.05)^10 - 1 )
p ≈ $7,571.86