The atomic mass of the following elements is provided: H: 1 D; C: 12 D; N: 14 D; O: 16 D; P: 31 D; S: 32 D; Cl: 35.5 D ; Na 23 D

Question

 

 

If one liter of H 3 PO 4 aqueous solution contains 0.98g of H 3 PO 4 , what is the molar concentration of this H 3 PO 4 solution?

Answer 1

To find the molar concentration of the H₃PO₄ solution, we need to follow these steps:

1. Calculate the molar mass of H₃PO₄:
2. H: 1 × 3 = 3
3. P: 31 × 1 = 31
4. O: 16 × 4 = 64
5. Total molar mass of H₃PO₄ = 3 + 31 + 64 = 98 g/mol
6. Determine the number of moles of H₃PO₄ in 0.98 g:
7. Number of moles = (\frac{\text{mass}}{\text{molar mass}})
8. Number of moles = (\frac{0.98 \text{ g}}{98 \text{ g/mol}} = 0.01 \text{ mol})
9. Calculate the molar concentration:
10. Molar concentration (M) = (\frac{\text{number of moles}}{\text{volume of solution in liters}})
11. Volume of solution = 1 liter
12. Molar concentration = (\frac{0.01 \text{ mol}}{1 \text{ L}} = 0.01 \text{ M})

Therefore, the molar concentration of the H₃PO₄ solution is 0.01 M.