Arturo O. answered 09/18/16
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The two integers are x and x + 1.
x2 + (x + 1)2 = 313
You can solve for x.
x2 + (x2 + 2x + 1) = 313
2x2 + 2x - 312 = 0
Divide by 2 to simplify a little:
x2 + x - 156 = 0
Factor the equation above and get
(x - 12)(x + 13) = 0
This gives two solutions: x = 12 or x = -13
Then x + 1 = 13 or -12
You have two pairs of consecutive integers that satisfy the conditions: 12 and 13; or -13 and -12
You can test to verify that both pairs satisfy the conditions.