
Kenneth S. answered 09/18/16
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It appears to me that we can approach this problem by placement of quantities (that will add up to exactly 75) along a number-line.
Start by placing point S, representing the amount s Sara receives, and then to its left, mark a point T with value s-8, for Tom's lesser amount.
Now, about Jan (point J): her amount must be s-3, so that Tom's amount is 5 dollars less than Jan.
Now, let's add up these amounts: s-8 + s-3 + s = 75. 3s - 11 = 75; 3s = 86.
Oh Oh! 86 /3 is an impossible number of dollars (28 and two thirds of one $).
So I'm saying the problem is defective (or impossible). Am I right?