Help Math 125

Question

An object is dropped from 3636 feet below the tip of the pinnacle atop a 520520?-ft tall building. The height hh of the object after tt seconds is given by the equation h equals negative 16 t squared plus 484h=−16t2+484. Find how many seconds pass before the object reaches the ground.

Answer 1

16t^2 = 484 ft

t^2 = 484/16

t^2 = 30.25

t = sqr30.25 = 5.5 seconds to hit the ground