David S. answered 09/13/16
Tutor
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(378)
CMU Grad to Help You Get the Big Ideas + Little Things in Science/Math
I usually approach these sort of problems by drawing a diagram to help me sort things out. I'll use G for good and D for defective. I'll list the pairs of possible choices by writing what's possible for the first draw to the left (5 choices), then what is possible for the second draw on the right (4 choices). The key here is to think about the fact that all of the good batteries are really unique -- kind of like if they each looked different (like a brand label) or something like that, and not just Good.
→G
G →G
→G
→D
→G
G →G
→G
→D
G →G
→G
→D
→G
G →G
→G
→D
G →G
→G
→D
→G
G →G
→G
→D
G →G
→G
→D
→G
D →G
→G
→G
D →G
→G
→G
So the sample space for this problem looks like all twenty of these written out and put inside braces, each separated by commas. These don't have to be in any particular order as long as you've written out all of the individual possible outcomes, even if they repeat, like this one does quite a lot! Not very exciting for a problem, but it should show you why the same space is much more than {G-G, G-D}.
Shelby S.
Also, how would I find the probability of the following events:
The first battery is good or the second battery is good, or both are good. Round your answer to the nearest hundredth.
The first battery is good or the second battery is good, or both are good. Round your answer to the nearest hundredth.
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09/15/16

David S.
tutor
The nice thing about sample sets is that you get to see all the possible ways that meet a particular criteria, like "both batteries good," and are inside the set, so you can count them up. So for this part, how many G-G are in your set, or in the above diagram for that matter? Probability is the ratio (that usually looks like a fraction) of what you are asked to find (the stuff that meets the criteria) compared to the total number of all possible outcomes (20 in this case). Since most of the set is G-G you should be getting a final answer, in decimal form, that is closer to 1.00 than to 0.00 when you actually "do the division" that the fraction you wrote represents.
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09/16/16

David S.
tutor
I like to think of OR conditions as allowing me to count a possible outcome that meets EITHER of the criteria that are joined by the "or", as opposed to an AND condition that I think of as ONLY IF BOTH. So in this case any possible way in your sample set that has a G in it, even those with a double G, count towards meeting this statement (the three criteria). The thing to remember is not to double count: add the number of G-D's to the D-G's then to the G-G's to get your total, then divide that by the overall number in the sample set (20). Express your final result as a number between 0.00 and 1.00 since this is the range that probability can be ("nothing" to "all"). If your final result is greater than 1.00 then that's a pretty good indication that some sort of double counting happened. Hope these help!
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09/16/16
Shelby S.
Both batteries are good (5 points) Enter in decimal form and round to the nearest hundredth.
09/15/16