
Karin S. answered 09/05/16
Tutor
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Math Praxis Tutor Helping Students Pass Math Section!
the distance for each trip is the same and the distance is speed times time. So set up the equation where S is Sunday speed and F is Friday speed
4S=3F
and also we are told that
S=F-10
now sibstitude the 2nd equation into the 1st.
4(F-10)=3F
4F-40=3F
solving we have F=40mph
therefore S=40-10=30mph.
As a check be sure he travels the same distance each day (40)(3)=120=(30)(4)
it checks.