Karin S. answered • 09/05/16

Math Praxis Tutor Helping Students Pass Math Section!

the distance for each trip is the same and the distance is speed times time. So set up the equation where S is Sunday speed and F is Friday speed

4S=3F

and also we are told that

S=F-10

now sibstitude the 2nd equation into the 1st.

4(F-10)=3F

4F-40=3F

solving we have F=40mph

therefore S=40-10=30mph.

As a check be sure he travels the same distance each day (40)(3)=120=(30)(4)

it checks.