The example how you get the answer

Question

What is the weight of the plain carbon steel used in the construction of a cylinder that has a radius of 5" and a height of 24" assume 1/2" thick steel is the material used?

Answer 1

V = πr²h, is the volume of a cylinder, where r = radius,h = height of cylinder

 

the thickness of the material is 1/2 inch. Therefore, we must remove the hollow section of the cylinder inside. We do this by subtracting the smaller cylinder. The height of the cavity will be h - 2t and the radius will be r - t.

 

Therefore the equation for the volume of the steel is:

 

V = πr²h - π(r - t)²(h - 2t), where t = thickness of steel.

 

W = Vd, where d = density of the plain carbon steel.

 

d can be looked up in a materials table.

 

note: make sure all the units are compatible, density should be in pounds/square inch. If not make sure to convert. For example, if the density is given as 2 lbs/ft² convert by multiplying by 1ft²/144in². Also do not confuse mass with weight. mass is a measure of the quantity of matter, while weight is a measure of the force of a mass due to gravity. Grams are not the same as Newtons and pound mass is not the same as pound force.