Determine the x-intercepts of the parabola.

Question

please help me, I've done this a billion times.

 

A parabola of the form y=ax2+bx+c has a vertex located at x=2. The y-coordinate of the parabola at x=5 is
0/6
. The y-coordinate of the parabola at x=7 is
−32/6
. Determine the x-intercepts of the parabola.

Answer 1

y=a(x-2)(x-5)

-32/6= -16/3= a(7-2)(7-5)=10a

a=-8/15

y=-(8/15)(x^2-7x+10)

y= -8x^2/15 +56x/15 -16/3