Length and width

Question

The perimeter of the rectangle Plainfield is 346 yards. The length of the field is 7 yards less than double the width. what are the dimensions of the playing field?

Answer 1

perimeter = 2L + 2W = 346

 

L = W-7

substitute that back in

 

2(W-7) + 2W = 346

2W - 14 + 2W = 346

4W - 14 = 346

4W = 360

W = 360/4

W = 90 yds

 

L = W-7 = 83 yds

 

The field is 83 yds by 90 yds

 

check: 2(83) + 2(90)

         = 166 + 180

         = 346 yds