
Kenneth S. answered 07/28/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
If someone is totally confused, the explanation ought to be undertaken step by step.
The idea is based on an IDENTITY. Suppose that a proposition (e.g. formula) depending on positive integer k is true.
IF I CAN SHOW THAT IT NECESSARILY FOLLOWS that the Proposition must also be true for k+1 (instead of just k)--this is a GENERALIZATION--then I would test the proposition for k=1. (This would be considered the starter-value; the truth of the proposition when k = 1 is a simple empirical demonstration.)
If that's true, then our generalization (Prop. k true implies prop. k+1 MUST ALSO BE TRUE), then the proposition is true, consequently, for k=2.
It being true for k=2, our generalization is used, again, showing that it has to be true for k=3. (We keep increasing k by 1 each time that we apply the generalization implication). And so, reasoning thus ad infinitum, the proposition is true for all positive integers.