This is the normal approximation to the binomial where p=.289+.156+.135=.580 so q=1-p=.420
z=(X-np)/sqrt(npq)
p(X<=676)=
z=(676-1223*.58)/sqrt(1223*.58*.42)
z=-1.9
so probability =.0287
Karen D.
asked 07/28/16
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Christopher T.
01/11/17