
Norbert W. answered 07/26/16
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Math and Computer Language Tutor
Let v be the speed Praedup.
Then the speed of Kathy is (v+8)
In time t, Praedup goes v * t = 57 and Kathy goes (v + 8) * t = 81
(v * t)/((v + 8)*t) = v/(v+8) = 57/81 = 19/27
Cross multiply: 27v = 19(v + 8)
27v = 19v + 152
8v = 152
v = 19 km/hr
Praedup rides at19 km/hr and Kathy at 27 km/hr
Then the speed of Kathy is (v+8)
In time t, Praedup goes v * t = 57 and Kathy goes (v + 8) * t = 81
(v * t)/((v + 8)*t) = v/(v+8) = 57/81 = 19/27
Cross multiply: 27v = 19(v + 8)
27v = 19v + 152
8v = 152
v = 19 km/hr
Praedup rides at19 km/hr and Kathy at 27 km/hr