Jack usually mows his lawn in 44 hours. Marilyn can mow the same yard in 33 hours. How much time would it take for them to mow the lawn? together?

Question

Jack usually mows his lawn in 44 hours. Marilyn can mow the same yard in 33 hours. How much time would it take for them to mow the lawn? together?

Answer 1

In one hour Jack mows 1/44 of the lawn. In t hours he mows t/44.

IN one hour Marilyn mows 1/33 of of the lawn, In t hours she mows t/33.

 

t/44 + t/33 = 1`

3t + 4t = 132       multiply by LCD

7t = 132              combine like terms

t ≈ 18.857