The period of a simple pendulum is represented by the formula t = 2\pi \sqrt {\frac{L}{{32}}} t=2pL32 where t is the period of the pendulum in seconds and L is

Question

The period of a simple pendulum is represented by the formula t = 2\pi \sqrt {\frac{L}{{32}}} t=2πL32 where t is the period of the pendulum in seconds and L is the length of the pendulum in feet.

What is the period of a 16 foot pendulum?

Answer 1

T = 2π√(L/g)

 

g = 32 ft/s²

 

L = 16 ft

 

T = 2π√(16/32) s = 2π√(1/2) s = 4.44 s